cz1
发表于 2024-2-25 18:59
鲁思顺老师:用你的方法,
求:\(x^{42}+y^{50}=z^{52}\)
cz1
发表于 2024-2-26 09:14
求:\(x^{22}+y^{26}+z^{34}+u^{38}=w^{46}\)
用:\(1^2+1^2+1^2+1^2=2^2\)
Treenewbee
发表于 2024-2-26 11:19
\[\left(2^{338} 3^{31} 5^{125}\right)^{42}+\left(2^{284} 3^{26} 5^{105}\right)^{50}=\left(2^{273} 3^{25} 5^{101}\right)^{52}\]
\[\left(2^{62} 3^{494} 5^{125}\right)^{42}+\left(2^{52} 3^{415} 5^{105}\right)^{50}=\left(2^{50} 3^{399} 5^{101}\right)^{52}\]
Treenewbee
发表于 2024-2-26 11:26
\[\left(2^{21879}\right)^{38}+\left(2^{24453}\right)^{34}+\left(2^{31977}\right)^{26}+\left(2^{37791}\right)^{22}=\left(2^{18074}\right)^{46}\]
cz1
发表于 2024-2-27 21:11
请教 Treenewbee,程中占的
A^11+B^13=C^17
A=a^181*b^170*c^91
B=a^153*b^144*c^77
C=a^117*b^110*c^59
其中,a、b、c为正整数,且a^2+b^2=c^2
是 (a, b, c)=(8, 15, 17) 还是 (a, b, c)=(15, 8, 17) ?
wlc1
发表于 2024-2-28 19:40
求:\(x^6+y^8+z^{10}=w^{14}\)
wlc1
发表于 2024-2-28 19:43
求:\(x^{10}+y^{24}+z^{26}=w^{34}\)
Treenewbee
发表于 2024-2-29 10:57
\[\left(2^{14} 3^{60}\right)^6+\left(2^{11} 3^{45}\right)^8+\left(2^9 3^{36}\right)^{10}=\left(2^6 3^{26}\right)^{14}\]
Treenewbee
发表于 2024-2-29 11:37
\[\left(2^{89} 3^{156}\right)^{10}+\left(2^{37} 3^{65}\right)^{24}+\left(2^{34} 3^{60}\right)^{26}=\left(2^{26} 3^{46}\right)^{34}\]
cz1
发表于 2024-2-29 19:23
杨传举先生的
令 x=y=a^n-1,
则 x^n+y^(n+1)=^n+^(n+1)=^n*=^n*a^n=^n,
则 x=y=a^n-1 及 z=a*(a^n-1) 才是方程 x^n+y^(n+1)=z^n 的通解!
式中a和n均为大于等于2的整数。
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