B(1)=1=1
B(2)=10=1
B(3)=11=2
B(4)=100=1
B(5)=101=2
B(6)=110=2
B(7)=111=3
B(8)=1000=1
B(9)=1001=2
B(10)=1010=2
B(11)=1011=3
B(12)=1100=2
B(13)=1101=3
B(14)=1110=3
B(15)=1111=4
B(16)=10000=1
B(17)=10001=2
{1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4,
5, 5, 6, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4,...}
- Table[DigitCount[n, 2, 1], {n, 120}]
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\(\displaystyle\exp\bigg(\sum_{n=1}^{\infty}\frac{B(n)}{n(n+1)}\bigg)=\exp\big(\ln(4)\big)=4\) |