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发表于 2023-10-21 22:22
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感兴趣的可以验证我在预印网站留下的评论:
According to my conclusion, we can make a bold prediction and verify: In all known convergence odd Collatz sequences, if start odd a multiply 3 plus 1 divided by 2^k(k>=3) get an odd, the corresponding odd of a in (*3+2^m-1)/2^k odd sequence is b, MSB bit of b is 2^n, then the count of all downward steps(k>=3) from a to final 1 is smaller than n! For example, Collatz odd 1893, corresponding odd is 2203, highest bit is 2^11, all downward steps(k>=3) of 1893 is 5<11. |
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