呼吁时代的落伍者，快跳出筛法解析数论的坭潭吧！

沟道效应

      谱法，是可以图示的，并且皆可用(9)式同一去其验证 后生孪生质数对wP-”与后生1+1质数对wP+” 的对数。下面本文将对后生孪生质数对和后生1+1质数对，从2N=6起，用(9)式去同一作验证。
     注意，我们称有k  项i vPc分布的区间为k势区间。故此，本文称2N=6与8是0势区间、2N=10至24是1势区间、2N=26至48是2势区间、…。而有验证登记册如下——

沟道效应

作者现在就对一些小值k势区间的全部2N含后生质数孪生数对与含后生质数1+1数对
同步作验证，供网友们点评。下面就是就是相应的验证资料——

0势````(6∈wP-”)=(3-2)×（1-0）=1`∈3~5````````````无误差   
区`````(6∈wP+”)=(3-2)×（1-0）=1`∈3+3`````````````无误差
间`````(8∈wP-”)=(4-2)×（1-0）=2`∈3~5、5~7````````无误差
```````(8∈wP+”)=(4-2)×（1-0）=2`∈3+5、5+3````````无误差

1势```(10∈wP-”)=(5-2)×（1-2/3）=1`∈5~7``````````````````````````无误差
区````(10∈wP+”)=(5-2)×（1-2/3）=1`∈5+5```````````````````````````无误差
间```` (12∈wP-”)=(6-2)×（1-2/3）≈1`∈5~7``````````````````````````无误差
``````(12∈wP+”)=(6-2)×（1-2/3）≈2`∈5+7、7+5````````````````````无误差
``````(14∈wP-”)=(7-2)×（1-2/3）≈2`∈5~7、11~13```````````````````无误差
``````(14∈wP+”)=(7-2)×（1-2/3）≈2`∈7+7``````````````````````````少1对
````` (16∈wP-”)=(8-2)×（1-2/3）=2`∈5~7、11~13````````````````````无误差
``````(16∈wP+”)=(8-2)×（1-2/3）=2`∈5+11、11+5````````````````````无误差
``````(18∈wP-”)=(9-2)×（1-2/3）≈2`∈5~7、11~13```````````````````无误差
``````(18∈wP+”)=(9-2)×（1-2/3）*2/1`≈4`∈5+13、7+11、11+7、13+5``无误差
``````(20∈wP-”)=(10-2)×1/3`≈2`∈5~7、11~13、17~19````````````````多1对
注意，此处20可被5整除，但此时的5不属于前生奇质数，故在此处计算20∈wP+不能作加乘增浮系数的
操作，待到2势区间的40时，5就属于前生奇质数，故到时就必须作加乘增浮系数的操作。
`````(20∈wP+”)=(10-2)×（1-2/3）≈2`∈7+13、13+7````````````````````无误差
1势``(22∈wP-”)=(11-2)×（1-2/3）=3`∈5~7、11~13、17~19```````````````无误差
区```(22∈wP+”)=(11-2)×（1-2/3）=3`∈5+17、11+11、17+5```````````````无误差
间```(24∈wP-”)=(12-2)×（1-2/3）≈3`∈5~7、11~13、17~19``````````````无误差
`````(24∈wP+”)=(12-2)×（1-2/3）*2/1`≈6`∈5+19、7+17、11+13、
`````````````````````````````````13+11、17+7、19+5````````````无误差

lusishun

lusishun 发表于 2019-8-7 05:19
再说两筛，首先要有等差互补数列的性质规律的发现，没有这点为基础，都是猜。
定义：和（差）为定值的两 ...

性质：等差互补（项同）数列所含倍数含量相等

这个性质规律的发现最为重要，认识到这一点，才保证，两筛法的可行性，用加强比例两筛法，最后生效的数对，才是素数对。

举例：两个数列，1,2,3,4,5，...........................，500‘       （A）
                         999,998,997,996,995,994，......500.         (B)
这两个数列是等差互补数列，即对应项的和等于1000，’
在数列（A）与（B）中，任何一个数p的倍数含量是相等的，都是500/p,

另筛掉（A)中7的倍数，7,14,21,28,35,42，..........            497
    带走数列（B）中的  993,986,979,972,965,958，..........503
这又是两个等差互补数列，在这两个数列中出去7，以外，其他任何数的倍数含量是相等的，

筛去数列（A）中7的倍数含量，叫主筛，带走数列（B）中的数，就叫作从筛。
筛去数列（A）中7的倍数含量，还暗筛了数列（A）中2,3,5,11,13,17,19.......的倍数含量
筛去数列（A）中7的倍数含量，还从筛了筛去数列（B）中2，3，5，11，13，17，19......的倍数含量,且数量是相等的，

lusishun

lusishun 发表于 2019-8-8 00:47
性质：等差互补（项同）数列所含倍数含量相等

这个性质规律的发现最为重要，认识到这一点，才保证，两 ...

简单比例两筛法，求和为1000的素数对，不少于：

(1000/2)（1-4/7）（1-26/36）（1-2/3）（1-2/5）（1-2/7）（1-2/11）（1-2/13）（1-2/17）（1-2/19）（1-2/23）(1-2/29)=暂且不算了

沟道效应

下面，我们把（1-2/5）直接写成1/5，以简化计算式写法，至此之后，我们直接把（1-2/ivP）
写作1/ivP，以减轻写作负担。
2势``(26∈wP-”)=(13-2)×1/5`≈2`∈11~13、17~19`````````````````````````````无误差
区```(26∈wP+”)=(13-2)×1/5`≈2`∈7+19、13+13、19+7````````````````````````多1对
间```(28∈wP-”)=(14-2)×1/5`≈2`∈11~13、17~19`````````````````````````````无误差
`````(28∈wP+”)=(14-2)×1/5`≈2`∈11+17、17+11`````````````````````````````无误差
`````(30∈wP-”)=(15-2)×1/5`≈2`∈11~13、17~19`````````````````````````````无误差
`````(30∈wP+”)=(15-2)×1/5*2/1*4/3`≈6`∈7+23、11+19、13+17、
``````````````````````````````````````17+13、19+11、23+7``````````````````无误差
`````(32∈wP-”)=(16-2)×1/5`≈2`∈11~13、17~19、29~31``````````````````````多1对
`````(32∈wP+”)=(16-2)×1/5`≈2`∈13+19、19+13`````````````````````````````无误差
`````(34∈wP-”)=(17-2)×1/5`=3`∈11~13、17~19、29~31```````````````````````无误差
`````(34∈wP+”)=(17-2)×1/5`=3`∈11+23、17+17、23+11```````````````````````无误差
`````(36∈wP-”)=(18-2)×1/5`≈3`∈11~13、17~19、29~31``````````````````````无误差
`````(36∈wP+”)=(18-2)×1/5*2/1`≈6`∈7+29、13+23、17+19、
``````````````````````````````````19+17、23+13、29+7``````````````` ``````无误差
`````(38∈wP-”)=(19-2)×1/5`≈3`∈11~13、17~19、29~31`````````````` ```````无误差
`````(38∈wP+”)=(19-2)×1/5`≈6`∈7+31、19+19、31+7```````````````` ```````无误差
`````(40∈wP-”)=(20-2)×1/5`≈3`∈11~13、17~19、29~31``````````````` ``````无误差
`````(40∈wP+”)=(20-2)×1/5*4/3`≈4`∈11+29、17+23、23+17、29+11````` `````无误差
注意，到此处作加乘增浮系数的操作，与前面20时不作加乘增浮系数的操作，两相比较，就体现了
验证式有内在根据的科学性，这是解析数论无论如果怎样作加强解析，也是无能为力的。
2势``(42∈wP-”)=(21-2)×1/5`≈3`∈11~13、17~19、29~31``````````````````````无误差
区```(42∈wP+”)=(21-2)×1/5*2/1`≈7`∈11+31、13+29、19+23、
间`````````````````````````````````23+19、29+13、31+11`````````````  ``````少1对
`````(44∈wP-”)=(22-2)×1/5`=4`∈11~13、17~19、29~31、41~43`````````````````无误差
`````(44∈wP+”)=(22-2)×1/5`=4`∈7+37、13+31、31+13、37+7``````````````````无误差
`````(46∈wP-”)=(23-2)×1/5`≈4`∈11~13、17~19、29~31、41~43````````````````无误差
`````(46∈wP+”)=(23-2)×1/5`≈4`∈17+29、23+23、29+17```````````````````````少1对
`````(48∈wP-”)=(24-2)×1/5`≈4`∈11~13、17~19、29~31、41~43````````````````无误差
`````(48∈wP+”)=(24-2)×1/5*2/1`≈7`∈7+41、11+37、17+31、19+29、
```````````````````````````````````29+19、31+17、37+11、41+7````````` `````多1对

沟道效应

与下一楼同

沟道效应

按2势系数继续进行计算，当有(50∈wP+”)=(25-2)×1/5×4/3`≈6，但实际上50属于第3势区间偶数，
计算数对应缩小为4，其差别，可见于第3势区间的(50∈wP+”)的实际计算。下面进入3势区间（7^2
与11^2区间）作验证。
     此处，公式实际为延传为：（N-2）×(1-2/3)(1-2/5)(1-2/7)可简化为：（N-2）×1/7。即第3势区刘
的验证表，可简略为——
3势``(50∈wP-”)=(25-2)×1/7`≈3`∈11~13、17~19、29~31、41~43```````````````````多1对
区```(50∈wP+”)=(25-2)×1/7×4/3`≈4`∈13+37、19+31、31+19、37+13``````````````无误差
间```(52∈wP-”)=(26-2)×1/7`≈3`∈11~13、17~19、29~31、41~43```````````````````多1对
（1）(52∈wP+”)=(26-2)×1/7`≈3`∈11+41、23+29、29+23、41+11```````````````````多1对
`````(54∈wP-”)=(27-2)×1/7`≈3`∈11~13、17~19、29~31、41~43```````````````````多1对
`````(54∈wP+”)=(27-2)×1/7×2/1`≈7`∈11+43、13+41、17+37、23+31、
````````````````````````````````````31+23、37+17、41+13、43+ 11````````````多1对
`````(56∈wP-”)=(28-2)×1/7`≈3`∈11~13、17~19、29~31、41~43```````````````````多1对
`````(56∈wP+”)=(28-2)×1/7×6/5`≈4`∈13+43、19+37、37+19、43+13``````````````无误差
`````(58∈wP-”)=(29-2)×1/7`≈3`∈11~13、17~19、29~31、41~43```````````````````多1对
`````(58∈wP+”)=(29-2)×1/7`≈3`∈11+47、17+41、29+29、41+17、47+11```````````多2对
`````(60∈wP-”)=(30-2)×1/7`=4`∈11~13、17~19、29~31、41~43``````````````````无误差
`````(60∈wP+”)=(30-2)×1/7*2/1*4/3`≈10`∈13+47、17+43、19+41、23+37、29+31、
`````````````````````````````````31+29、37+23、41+19、43+17、47+13````````无误差

lusishun

那些还在叫卖筛法成就的人，已是时代的落伍者，快跳出筛法解析数论的坭潭吧！不要一张口，就是单筛、双筛、明筛、暗筛、加强筛，各筛各的，没完没了地筛，似乎八仙过海，各显神通广大，结果，尽最大努力而终难得比岸，快醒悟吧！

我把单筛、两筛、明筛、暗筛、加强筛，各筛各的，没完没了地筛，又叫卖了一次，并且还增加了主筛，从筛，
我估计楼主就没看，没有兴趣，继续下去，拜拜

沟道效应

3势``(62∈wP-”)=(31-2)×1/7`≈4`∈11~13、17~19、29~31、41~43、59~61````````````多1对
区```(62∈wP+”)=(31-2)×1/7`≈4`∈19+43、31+31、43+19``````````````````````````少1对
间```(64∈wP-”)=(32-2)×1/7`≈4`∈11~13、17~19、29~31、41~43、59~61````````````多1对
（2）(64∈wP+”)=(32-2)×1/7`≈4`∈11+43、17+47、41+43、43+41、47+17、43+11`````多2对
`````(66∈wP-”)=(33-2)×1/7`≈4`∈11~13、17~19、29~31、41~43、59~61````````````多1对
`````(66∈wP+”)=(33-2)×1/7*2/1`≈8`∈13+53、19+47、23+43、29+37、37+29、
````````````````````````````````````43+23、47+19、53+13````````````````````无误差
`````(68∈wP-”)=(34-2)×1/7`≈4`∈11~13、17~19、29~31、41~43、59~61````````````多1对
`````(68∈wP+”)=(34-2)×1/7`≈4`∈19+49、31+37、37+31、49+19```````````````````无误差
`````(70∈wP-”)=(35-2)×1/7`≈4`∈11~13、17~19、29~31、41~43、59~61````````````多1对
`````(70∈wP+”)=(35-2)×1/7*4/3`≈6`∈11+59、17+53、23+47、29+41、41+29、
````````````````````````````````````47+23、53+17、59+11````````````````````多2对

沟道效应

3势``(72∈wP-”)=(36-2)×1/7`≈4`∈11~13、17~19、29~31、41~43、59~61``````````````多1对
区```(72∈wP+”)=(36-2)×1/7*2/1`≈9`∈11+61、13+59、19+53、29+43、31+41、
间`````````````````````````````````41+31、43+29、53+19、59+13、61+11````````多1对
（3）(74∈wP-”)=(37-2)×1/7`=5`∈11~13、17~19、29~31、41~43、59~61、71~73```````多1对
`````(74∈wP+”)=(37-2)×1/7`=5`∈13+61、31+43、37+37、43+41、61+13`````````````无误差
`````(76∈wP-”)=(38-2)×1/7`≈5`∈11~13、17~19、29~31、41~43、59~61、71~73``````多1对
`````(76∈wP+”)=(38-2)×1/7`≈5`∈17+59、23+53、29+47、47+29、53+23、59+17``````多1对
`````(78∈wP-”)=(39-2)×1/7`≈5`∈11~13、17~19、29~31、41~43、59~61、71~73``````多1对
`````(78∈wP+”)=(39-2)×1/7*2/1`≈10`∈11+67、17+61、19+59、31+47、37+41
`````````````````````````````````````41+37、47+31、59+19、61+17、67+11``````无误差
`````(80∈wP-”)=(40-2)×1/7`≈5`∈11~13、17~19、29~31、41~43、59~61、71~73```````多1对
`````(80∈wP+”)=(40-2)×1/7*4/3`≈7`∈13+67、19+61、37+43、43+37、61+19、67+13```少1对