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至今有谁人能解释"偶数值增大时素数对值忽高忽低"吗?
能证明,多好。
在标准的限制条件下,x,y不能整除3,4,5,是符合限制条件的正整数,以3*4*5=60作为循环周期,能整除3,4,5的数,其解的组数最多,不能整除3,4,5的数其解的组数最少。下面是60类数的表达式,和近似求解的普通公式(一代全)。
N值→→准确公式
60t+1→→6t+0
60t+2→→6t+1
60t+3→→12t+2
60t+4→→9t+1
60t+5→→8t+0
60t+6→→12t+0
60t+7→→6t+0
60t+8→→9t+2
60t+9→→12t+2
60t+10→→8t+0
60t+11→→6t+0
60t+12→→18t+2
60t+13→→6t+2
60t+14→→6t+3
60t+15→→16t+4
60t+16→→9t+2
60t+17→→6t+0
60t+18→→12t+4
60t+19→→6t+2
60t+20→→12t+4
60t+21→→12t+4
60t+22→→6t+1
60t+23→→6t+2
60t+24→→18t+8
60t+25→→8t+4
60t+26→→6t+3
60t+27→→12t+4
60t+28→→9t+5
60t+29→→6t+2
60t+30→→16t+8
60t+31→→6t+4
60t+32→→9t+4
60t+33→→12t+8
60t+34→→6t+3
60t+35→→8t+4
60t+36→→18t+10
60t+37→→6t+4
60t+38→→6t+5
60t+39→→12t+8
60t+40→→12t+8
60t+41→→6t+4
60t+42→→12t+8
60t+43→→6t+6
60t+44→→9t+7
60t+45→→16t+12
60t+46→→6t+3
60t+47→→6t+4
60t+48→→18t+16
60t+49→→6t+6
60t+50→→8t+8
60t+51→→12t+10
60t+52→→9t+7
60t+53→→6t+6
60t+54→→12t+12
60t+55→→8t+8
60t+56→→9t+8
60t+57→→12t+10
60t+58→→6t+5
60t+59→→6t+6
60t+60→→24t+24
上边是求x+y=N的符合条件的正整数解的组数公式,条件是x,y不能被3,4,5整除,即它们不是3,4,5的倍数。周期t可以取任何自然数(包括0),即N可以取任何自然数(包括0)。与其对应的近似值普通公式是:调节系数*N*[(1-1/3)*(1-1/4)*(1-1/5)]^2=调节系数*(0.16N), 调节系数=3*(3-1V2)/(3-1)^2*4*(4-1V2)/(4-1)^2*5*(5-1V2)/(5-1)^2=60*(3-1V2)*(4-1V2)*(5-1V2)/576,说明,当给的N值是其倍数时(含因子3,4,5时)取1,否则取2.
标准公式计算值与普通公式计算值的相对误差随t的增大而减小,绝对误差每个周期都一致.最大正负误差为1.7,累计误差为0. |
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