陳全億 发表于 2021-4-3 09:43

關於複值函數的Mobius inversion formula

先前在Wikipedia上看到了關於複值函數的Mobius inversion formula公式,但是上面並沒有放上證明,也找不到引用的是哪本書籍,以下為其中內容:
內容:

A related inversion formula more useful in combinatorics is as follows: suppose F(x) and G(x) are complex-valued functions defined on the interval [1,∞) such that
G(x)=summation(1<=n<=x){F(x/n)} for all x>=1
then
F(x)=summation(1<=n<=x){μ(n)*G(x/n)} for all x>=1       μ(n) is Mobius μ function

請問是否有人知道此證明抑或知道要看哪本書找此式的證明,煩請不吝賜教告知,謝謝!   
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